0=-16t^2+64t+82.7

Solution for 0=-16t^2+64t+82.7 equation:

0=-16t^2+64t+82.7

We move all terms to the left:

0-(-16t^2+64t+82.7)=0

We add all the numbers together, and all the variables

-(-16t^2+64t+82.7)=0

We get rid of parentheses

16t^2-64t-82.7=0

a = 16; b = -64; c = -82.7;
Δ = b2-4ac
Δ = -642-4·16·(-82.7)
Δ = 9388.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-\sqrt{9388.8}}{2*16}=\frac{64-\sqrt{9388.8}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+\sqrt{9388.8}}{2*16}=\frac{64+\sqrt{9388.8}}{32}
$